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snow_lady [41]
3 years ago
6

Which of the following can computer maintenance software determine?

Computers and Technology
1 answer:
Softa [21]3 years ago
7 0

Answer:

A

Explanation:

Becuase i picked that and i git it right

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I need answer poooo<br>​
Fiesta28 [93]

Answer:

what is this?Are yhere any options for this question ❓

7 0
3 years ago
Write a function call it isEvenPositiveInt which takes an integer x and return true if x is positive and also even. Note isinsta
Anna11 [10]

Answer:

The program to this question as follows:

Program:

def isEvenPositiveInt(x): #defining method isEvenPositiveInt

   if x>0: #checking number is positive or not

       if x%2==0: #check true condition

           return True #return value True

       else:

           return False #return value False

   return False #return value False

print(isEvenPositiveInt(24)) #calling method and print return value

print(isEvenPositiveInt(-24)) #calling method and print return value

print(isEvenPositiveInt(23)) #calling method and print return value

Output:

True

False

False

Explanation:

In the above Python program, a method "isEvenPositiveInt" is defined, that accepts a variable "x" as its parameter, inside the method a conditional statement is used, which can be described as follows:

  • In the if block the condition "x>0" is passed, that check value is positive, if this condition is true, it will go to another if block.
  • In another, if block is defined, that checks the inserted value is even or not, if the value is even it will return "true", otherwise it will go to the else part, that returns "false".  
5 0
3 years ago
Some problems are better solved by a computer and some are better solved by humans.
aalyn [17]

Answer:

I say when u don't know the answer completly.

3 0
3 years ago
Suppose that the tuition for a university is $10,000 this year and increases 4% every year. In one year, the tuition will be $10
Nataliya [291]

Answer:

<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>

tuition = 10000

rate = 0.04

for i in range(1,15):

tuition = tuition + tuition * rate

if i <= 10:

print("Year "+str(i)+" tuition:",end=" ")

print(round(tuition,2))

if i == 14:

print("Tuition 4th year after:",end=" ")

print(round(tuition,2))

Explanation:

<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>

tuition = 10000

rate = 0.04

<em>The next line iterates from year 1 to year 14</em>

for i in range(1,15):

<em>This line calculates the tuition for each year</em>

tuition = tuition + tuition * rate

<em>The next 3 lines prints the tuition for year 1 to year 10</em>

if i <= 10:

print("Year "+str(i)+" tuition:",end=" ")

print(round(tuition,2))

<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>

if i == 14:

print("Tuition 4th year after:",end=" ")

print(round(tuition,2))

5 0
3 years ago
HELP ASAP WILL GIVE BRAINLY Question 19 Multiple Choice Worth 5 points) (05 03 MC) Network technologies specialist Hannah has be
nasty-shy [4]

Network technologies specialist Hannah would need to configure: C. RIP version 2 using Internet Protocol Version 4 (TCP/IPv4).

<h3>What is RIP?</h3>

RIP is an acronym for Routing Information Protocol and it can be defined as an intradomain routing protocol which is typically designed and developed based on distance vector routing.

<h3>The types of RIP.</h3>

In Computer networking, there are two main types of Routing Information Protocol (RIP) and these include:

  • RIP version 1.
  • RIP version 2.

RIP version 2 are generally designed and developed to include subnet masks unlike RIP version 1. Thus, Hannah would need to configure RIP version 2 using Internet Protocol Version 4 (TCP/IPv4) allow several machines on different subnets to communicate with each other using broadcasts.

Read more on routing protocol here: brainly.com/question/24812743

4 0
2 years ago
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