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3 years ago

In the circle below, find x and y

Mathematics

2 answers:

olga55 [171]3 years ago

6 0

Answer:

Hjdjdn

Step-by-step explanation:Bxnxnn

arlik [135]3 years ago

6 0

Answer:

x and y

Step-by-step explanation:

x+y

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Vikki [24]

Answer:

TIK TOK

Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

Simplify the expression

Ronch [10]

Answer:

(3 x)/(5 x + 2)

Step-by-step explanation:

Simplify the following:

(3 x^2)/(5 x^2 + 2 x)

Hint: | Factor common terms out of 5 x^2 + 2 x.

Factor x out of 5 x^2 + 2 x:

(3 x^2)/(x (5 x + 2))

Hint: | For all exponents, a^n a^m = a^(n + m). Apply this to (3 x^2)/(x (5 x + 2)).

Combine powers. (3 x^2)/(x (5 x + 2)) = (3 x^(2 - 1))/(5 x + 2):

(3 x^(2 - 1))/(5 x + 2)

Hint: | Evaluate 2 - 1.

2 - 1 = 1:

Answer: (3 x)/(5 x + 2)

8 0

3 years ago

Read 2 more answers

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Devon purchased tickets to an air show for 9 adults and 2

Vladimir79 [104]

Answer:

18$ per adult, 15 per clild

Step-by-step explanation:

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6 0

2 years ago

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PLEASE HELP ASAP Due in 1 day!!!

Helen [10]

Step-by-step explanation:

Q1 . (f+g)(x) = f(x) + g(x)

=4x-4 +2x^2 -3x

= 2x^2 + x -4

Q2. (f-g)(x) = f(x) - g(x)

= 2x^2−2 - (4x+1)

= 2x^2 -2 -4x -1

= 2x^2 - 4x -3

Q3. h(x)=3x−3 and g(x)=x^2+3

(h.g)(x) = h(x) × g(x)

= (3x-3) × (x^2 + 3)

=3x^3 -3x^2 + 9x -9

Q4.f(x)=x+4 and g(x)=x+6

(f/g)(x) = f(x) ÷ g(x)

= x+4 / x+6

the domain restriction is x>-6

x<-6

x doesn't equal (-6)

7 0

2 years ago