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3 years ago

If you took a true “if then” statement and instead a not in each clause the new statement would also be true

Mathematics

2 answers:

Strike441 [17]3 years ago

4 0

Answer:

True

Step-by-step explanation:

If it snows today, I will have to go out and clean the driveway.
If it does not snow today, I will not have to out and clean the driveway.
Without going into p's and q's and true false tables, I believe the negation is also true.

koban [17]3 years ago

3 0

Answer:

Step-by-step explanation:

If a then b is true then not b = not a is true. This is called the contrapositive.

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6! = (4! x (6-4)!) =<br>

Eduardwww [97]

Answer:

Step-by-step explanation:

n! = 1 · 2 · 3 · 4 · ... · n

6! = 1 · 2 · 3 · 4 · 5 · 6 = 720

(4! × (6 - 4)!) = (1 · 2 · 3 · 4 × 2!) = 24 × 1 · 2 = 24 × 2 = 48

5 0

3 years ago

(b) 33 is 75% of what number?

miskamm [114]

Your answer should be 44 lol

8 0

3 years ago

Read 2 more answers

How do you solve -6(a+8)

algol [13]

Use the distributive property.

This states that: a(b+c)= ab+ac

So,

-6*a= -6a and -6*8= -48

-6a+-48

This is the most you can simplify this problem.

I hope this helps!
~kaikers

4 0

4 years ago

Read 2 more answers

Hey guys umm help me

gavmur [86]

The answer is c

1/6 divided by 1/2

i had this question on my own

3 0

3 years ago

Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

TiliK225 [7]

Answer:

$\dfrac{9}{25}$

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }$

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

$P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}$

Now, the <em>required probability</em> can be found as:

$P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }$

3 0

3 years ago