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3 years ago

The impacts of El Niño upon climate in temperate latitudes show up most clearly during which season?

2 answers:

6 0

The impacts of El Nino last 9-12 months but are most heavily felt during Winter. The term El Nino refers to the climate cycle that affects the countries in temperature latitudes, and that is characterized by temperature increase in the ocean, and rainfall due to stormy weather, make a shift to the East.
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zlopas [31]3 years ago

4 0

so the answer would be winter

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The Great Lakes and Corn Belt occupies a significant portion of this subregion located between the Appalachian Mountains to the

IRISSAK [1]

Answer:

The Great Lakes and Corn Belt occupies a significant portion of this subregion located between the Appalachian Mountains to the east and the Rocky Mountains to the west named A. America’ s central lowlands.

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3 years ago

What is the value of X6? <br><br> Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

2 years ago

Suppose that a space telescope has been designed that can produce sharp images in visible light. Then a proposal is made to rede

Elenna [48]

Answer:

F. The telescope will be less able to detect dim objects, and it will be less able to resolve fine detail especially at longer wavelength

Explanation:

The telescope will be less able to detect dim object due to it's small aperture and can't also resolve fine and bright image.

6 0

2 years ago

How does the surface area of a rock affect the rate at which it weathers?

vodka [1.7K]

At the point when the measure of the surface region with respect to volume builds, the rate of weathering increments. Weathering is the breakdown of rocks at the Earth's surface, by the activity of water, extremes of temperature, and natural action. It doesn't include the expulsion of shake material.

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2 years ago

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Overgrazing, overfarming, and the diversion of water for irrigation are significant causes of __________.

Dominik [7]

Its b deserttification

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3 years ago

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