So each house can hold 1000 cubes that are 1 meter in length. The house is also shaped like a cube, so you need to cube-root 1000. The cube-root of 1000 is 10. So the cube house has a length, width, and height of 10 meters.
One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:
– Multiplied: Add their exponents
– Divided: Subtract their exponents
We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have
[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]
For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us
5 1/2 + (-7) + (-5) = - 1 1/2 + (-5) = -6 1/2
And summing the terms in the second:
3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2
Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.
Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is
2^0, which is just 1.
Answer:
17.38*10^8
Step-by-step explanation:
Step one:
given data
The dividend is 2.26*10^8 (i rewrote the given data, i hope it was mearnt to be so)
divisor is 0.013.
Step two:
Hence the quotient is the whole number gotten when the dividend is divided by the divisor
quotient= 2.26*10^8/0.013.
quotient= 17.38*10^8
2.8 multiplied by 2.8 to find the surface area of the base which is 7.84
4*1/2*2.8*5.5 to find the surface area of all four triangular faces which is 30.8
Plus them together 7.84 plus 30.8 which is 38.64
If There is a math equation you can use math-way.
Also it would help if you can take a better picture.
Once you take a better picture I promise i will try my best to answer the question.
