Question

Find the product. (n 3) 3 · (n 4) 5 N

Answer 1

(n^3)^3 · (n^4)^5

=n^9 · n^20

=n^29

Answer 2

Answer:

$(n^{29}$.

Step-by-step explanation:

Given : $(n^{3})^{3} * (n^{4})^{5}$.

To find : Find the product.

Solution : We have given that

$(n^{3})^{3} * (n^{4})^{5}$.

By the exponent rule 1 ) $(x^{a})^{b} = x^{ab}$.

           Same base rule 2) $x^{a}* x^{b} = x^{a +b}$.

Then ,

$(n^{3})^{3} * (n^{4})^{5}$ = $(n^{9}* (n^{20}$.

Now, by rule 2.

$(n^{3})^{3} * (n^{4})^{5}$ = $(n^{29}$.

Therefore,  $(n^{29}$.