Question

∆ABC m∠B = 90° AB = 4 BC = 3 Find AC

Answer 1

Step-by-step explanation:

In ∆ABC, m∠B = 90°

Therefore ∆ABC is a right angled triangle with sides AB = 4 & BC = 3. AC is the hypotenuse.

Hence, by Pythagoras theorem:

$AC^2 = AB^2 +BC^2 \\ \\ \therefore \: AC = \sqrt{AB^2 +BC^2 } \\ = \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ = 5 \\ \\ \huge \red{ \boxed{ \therefore \: AC = 5 \: units}}$