X + y = 23000
x.08 + y.09 = 2040 
x = 23000 - y 
(23000 - y) .08 + y.09 = 2040 
1840 - .08y + .09y = 2040 
Simplify 
.01y = 200 
Simplify 
Y = 20000
X + 20000 = 23000 
X = 3000 
CHECK: .08x + .09(20000) = 2040 
.08x + 1800 = 2040 
Simply .08x = 240 
X = 3000 
        
             
        
        
        
<u>Answer:</u>
Consistent and dependent
<u>Step-by-step explanation:</u>
We are given the following equation:
1. 
2. 
3. 
For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with  which is the same as the equation number 2.
 which is the same as the equation number 2.
There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.
 
        
             
        
        
        
Based on the exchange rate, at the end of the trade, Lewis will have 31 puppets and 2 puzzles left over while Geppeto will have 158 puzzles and 4 puppets left over.
<h3>What is the exchange rate of puzzles for puppets?</h3>
The exchange rate of puzzles for puppets is 3 to 1.
Geppeto has 20 puppets to exchange for puzzles.
Lewis has 50 puzzles to exchange for puppets.
Number of times Lewis can exchange puzzles for puppets = 50/3 = 16 times.
Lewis will get 16 puppets in exchange for 48 puzzles.
Therefore;
Lewis will have 16 + 25 puppets = 31 puppets and 2 puzzles left over
Geppeto will have 48 + 100 puzzles = 158 puzzles and 4 puppets left over.
in conclusion, the exchange rate determines the how many puzzles and puppets will each one have after they complete their trade.
Learn more about exchange rate at: brainly.com/question/2202418
#SPJ1
 
        
             
        
        
        
Answer:
((3+5)/2,(6+11)/2)=(4,8.5)
 
        
             
        
        
        
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes
so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so
x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero
x³=0
x=0
x-∛3=0
x=∛3
x²+x∛3+∛9=0 has no solution
x+∛3=0
x=-∛3
x²-x∛3+∛9=0 has no solution
so the solutions are
x=-∛3, 0, ∛3