Answer: = -3g-4
Step-by-step explanation:
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
It would have 3 solutions
if you solve the equation how it is, it give 1 solution but if you make the 1 negative you get 2 more possibilities
Answer:
12
Step-by-step explanation:
18 -6
12
Hope that this helps you and have a great day :)
