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OLEGan [10]
3 years ago
12

How are observations different from inferences? (choose)

Mathematics
1 answer:
sergejj [24]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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Solve the equation.<br><br>-4 (y - 2) = 12<br><br>y = ?​
inna [77]
First you distribute what’s outside the parentheses (the -4)

-4•4= -4y
-4•-2= 8

New equation: -4y+8=12

Now you solve like a normal equation
12-8 is 4

New equation: -4y=4

Now divide

Answer:-1
8 0
2 years ago
A. 792 432,795<br> What is 432,795 divided by 792
Fittoniya [83]
It is 546.4583333333333, which would simplify to 546.46 if to the hundredths place or 546.5 to the tens place
8 0
3 years ago
Read 2 more answers
One number is 6 more than another. Twice the larger number is 5 times the smaller.
tresset_1 [31]

Answer:

The smaller number is 4

Step-by-step explanation:

Larger number = x

Smaller number = y

Write 2 equations

y + 6 = x

2x = 5y

Substitute x in the first equation to the second equation

2(y + 6) = 5y

Multiply 2(y + 6)

2y + 12 = 5y

Subtract 2y from both sides of the equation

12 = 3y

Divide both sides of the equation by 3

y = 4

x = y + 6 = 4 + 6 = 10

The smaller number is 4

Hope this helps :)

3 0
3 years ago
CAN SOMEBODY HELP ME??? giving brainliest!!! AREA!
Nikitich [7]

Answer:

Second option. "Sue wants to cover the lid of a box with paper. How much paper should she buy?"

Explanation:

The first option relies upon volume.

The last two options relies on side lengths.

The second option is relies on area because you have to calculate the area of the lid to know how much paper can be used to cover it.

8 0
3 years ago
Read 2 more answers
Suppose taxi fare from Logan Airport to downtown Boston is known to be normally distributed with a standard deviation of $2.50.
Mariulka [41]

Answer:

95% Confidence interval for taxi fare:  ($20.5,$24.2)

Step-by-step explanation:

We are given the following data set: for fares:

$22.10, $23.25, $21.35, $24.50, $21.90, $20.75, and $22.65

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{156.5}{7} = 22.35

95% Confidence interval:

\bar{x} \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

22.35 \pm 1.96(\frac{2.5}{\sqrt{7}} ) = 22.35 \pm 1.85 = (20.5,24.2)

6 0
2 years ago
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