F⁻¹(x) stands for the invers of function f(x). The inverse of f(x) is equal to x. We need to solve for x.
solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
x =

f⁻¹(x) =

Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) =

f⁻¹(4) =

f⁻¹(4) =

f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1
Answer:
The area of the triangle is 
Step-by-step explanation:
Given:
Coordinates D (0, 0), E (1, 1)
Angle ∠DEF = 60°
△DEF is a Right triangle
To Find:
The area of the triangle
Solution:
The area of the triangle is = 
Here the base is Distance between D and E
calculation the distance using the distance formula, we get
DE = 
DE =
DE = 
DE = 
Base = 
Height is DF
DF =
DF = 
DF = 
Now, the area of the triangle is
= 
=
=
=
By definition the area of a rectangle is:
A = l * w
Where,
l: long
w: width
So we have to clear the width:
w = A / l
Substituting the values:
w = (234) / (18) = 13
w = 13 feets
answer
the width, in feet, of the room is 13
Answer:
<h3>The answer is 0.5 m/s²</h3>
Step-by-step explanation:
To find the acceleration of an object given it's mass and the force acting on it can be found by using the formula

From the question
force = 5 N
mass = 10 kg
So we have

We have the final answer as
<h3>0.5 m/s²</h3>
Hope this helps you