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2 years ago

Solve the following proportion for v. V/13=11/13

Mathematics

1 answer:

NeX [460]2 years ago

8 0

Answer:

V = 11

Step-by-step explanation:

All you have to do here is to multiply both sides of this equation by 13. This will eliminate the fractions. You'll be left with V = 11.

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Aight ok so if i got two ducks and and i take one how munch is left

vichka [17]

Answer:

Step-by-step explanation:

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3 years ago

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A picture has a height that is 2 times it’s width . It is to be enlarged to an area of 128 in 2

morpeh [17]

9514 1404 393

Answer:

8 in by 16 in

Step-by-step explanation:

In your equation, we presume that x represents the width. Solving for x, we have ...

2x² = 128 . . . . . . given equation

x² = 64 . . . . . . . . divide by 2

x = √64 = 8 . . . . square root

The enlargement will be 8 inches by 16 inches.

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2 years ago

5+ =83 can someone help me out

enot [183]

You can do
83 - 5 to find the answer
So that's
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2 years ago

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Simplify the ratio of<br> 35 : 14

Ne4ueva [31]

Answer:

5:2

Step-by-step explanation:

divide both numbers by 7

hope this helps...

3 0

2 years ago

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A carpenter is putting a skylight in a roof. If the roof measures 10 + 8 by 8 + 6 and the skylight measures + 5 by 3 + 4, what i

Usimov [2.4K]

Answer:

The area is: $77x^2 + 105x + 28$ , option b.

Step-by-step explanation:

Rectangular area:

The area of a rectangular space is given bt the multiplication of its measures.

Area of the roof:

Dimensions of 10x + 8 and 8x + 6. So

$A_{r} = (10x+8)(8x+6) = 80x^2 + 60x + 64x + 48 = 80x^2 + 124x + 48$

Area of the skylight:

Dimensions of x + 5 and 3x + 4. So

$A_{s} = (x+5)(3x+4) = 3x^2+4x+15x+20 = 3x^2 + 19x + 20$

What is the area of the remaining roof after the skylight is built?

Total subtracted by the skylight, which is a subtraction of a polynomial, in which we subtract the like terms. So

$A_{r} - A_{s} = 80x^2 + 124x + 48 - (3x^2 + 19x + 20) = 80x^2 - 3x^2 + 124x - 19x + 48 - 20 = 77x^2 + 105x + 28$

The area is: $77x^2 + 105x + 28$ , option b.

3 0

2 years ago