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Dimas [21]
2 years ago
6

X - 3 = 8 4 Helppppppp

Mathematics
2 answers:
Misha Larkins [42]2 years ago
8 0

x-3 = 8×4

x-3 = 32

x = 32+3

x = 35

aivan3 [116]2 years ago
7 0
X=35 i hope this was right :)
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I need help please I will greatly appreciate it
Nataly_w [17]

Answer:

  B.  Square

Step-by-step explanation:

When in doubt, it can help to plot the points on a graph.

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By looking at the coordinate values, you see that the first two points have the same y-coordinate (0) and the other two points have the same y-coordinate (-4). These points are on horizontal lines that are 4 units apart.

Looking at the x-coordinates, you see that one pair of points has x-coordinates 4, and the other pair has x-coordinates 8. That is, these pairs of points are on vertical lines that are 4 units apart.

Vertical and horizontal lines are at right angles to each other. That means the figure must be a rectangle or square. The lengths of the sides are all 4 units, so the figure is a square.

3 0
2 years ago
Solve this exponential function 5^3m=125
Arlecino [84]

Answer:

m would be 1

Step-by-step explanation:

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8 0
3 years ago
25% of the student's in Mrs.Brown's class like chocolate ice cream. How many students are in her class if 6 students like chocol
Katen [24]

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24 students.

Step-by-step explanation:

25% is 1/4 of 100.

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7 0
3 years ago
Read 2 more answers
Help please, what’s: 5x-7+2-2x=-26
svetoff [14.1K]

Answer:

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Let's solve your equation step-by-step.

5x−7+2−2x=−26

Step 1: Simplify both sides of the equation.

5x−7+2−2x=−26

5x+−7+2+−2x=−26

(5x+−2x)+(−7+2)=−26(Combine Like Terms)

3x+−5=−26

3x−5=−26

Step 2: Add 5 to both sides.

3x−5+5=−26+5

3x=−21

Step 3: Divide both sides by 3.

3x

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−21

3

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x=−7

3 0
3 years ago
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Twenty-five students from Harry High School were accepted at Magic University. Of those students, 10 were offered athletic schol
Taya2010 [7]

Answer:

Step-by-step explanation:

Part A

For Athletic scholarship,

Mean = (16 + 24 + 20 + 25 + 24 + 23 + 21 + 22 + 20 + 20)/10 = 21.5

Standard deviation = √(summation(x - mean)²/n

n = 10

Summation(x - mean)² = (16 - 21.5)^2 + (24 - 21.5)^2 + (20 - 21.5)^2 + (25 - 21.5)^2 + (24 - 21.5)^2 + (23 - 21.5)^2 + (21 - 21.5)^2 + (22 - 21.5)^2 + (20 - 21.5)^2 + (20 - 21.5)^2 = 64.5

Standard deviation = √64.5/10 = 2.54

For non athletic scholarship,

Mean = (23 + 25 + 26 + 30 + 32 + 26 + 28 + 29 + 26 + 27 + 29 + 27 + 22 + 24 + 25)/15 = 26.6

n = 15

Summation(x - mean)² = (23 - 26.6)^2 + (25 - 26.6)^2 + (26 - 26.6)^2 + (30 - 26.6)^2 + (32 - 26.6)^2 + (26 - 26.6)^2 + (28 - 26.6)^2 + (29 - 26.6)^2 + (26 - 26.6)^2 + (27 - 26.6)^2 + (29 - 26.6)^2 + (27 - 26.6)^2 + (22 - 26.6)^2 + (24 - 26.6)^2 + (25 - 26.6)^2 = 101.6

Standard deviation = √101.6/15 = 2.6

This is a test of 2 independent groups. The population standard deviations are not known. it is a two-tailed test. Let 1 be the subscript for scores of athletes and 2 be the subscript for scores of non athletes.

Therefore, the population means would be μ1 and μ2

The random variable is x1 - x2 = difference in the sample mean scores of athletes and non athletes.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 21.5

x2 = 26.6

s1 = 2.54

s2 = 2.6

n1 = 10

n2 = 15

t = (21.5 - 26.6)/√(2.54²/10 + 2.6²/15)

t = - 4.65

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [2.54²/10 + 2.6²/15]²/[(1/10 - 1)(2.54²/10)² + (1/15 - 1)(2.6²/15)²] = 1.2008/0.1039

df = 12

We would determine the probability value from the t test calculator. It becomes

p value = 0.00056

Since alpha, 0.1 > than the p value, 0.00056, then we would reject the null hypothesis.

Therefore, these data provide convincing evidence of a difference in ACT scores between athletes and nonathletes.

Part B

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

For a 90% confidence level, the z score from the normal distribution table is 1.645

x1 - x2 = 21.5 - 26.6 = - 5.1

√(s1²/n1 + s2²/n2) = √(2.54²/10 + 2.6²/15) = 1.05

The confidence interval is - 5.1 ± 1.05

This analysis provides evidence that the mean scores for non athletes is higher than the mean scores for athletes, and that the difference between means in the population is likely to be between 4.05 and 6.15

4 0
3 years ago
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