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3 years ago

11

A triangle in the coordinate plane has coordinates of (2,3), (-4,-5), and (-2, 4). It is reflected about the y-axis. What are it

s new coordinates?

2 answers:

Anestetic [448]3 years ago

7 0

Answer:

I got A. (-2,3) (4,-5) (2,4)

chubhunter [2.5K]3 years ago

5 0

(-2,3) (4,-5) (2,4) you change the x value to to its opposite.

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Identify the figure

olya-2409 [2.1K]

Answer:

A

Step-by-step explanation:

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4 years ago

Triple a number decreased by 14

Ira Lisetskai [31]

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3 years ago

Solve the proportion. 8/11 = 4/y + 2

Rashid [163]

Answer:

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Step-by-step explanation:

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3 years ago

At a local print shop, 18 copies can be made for $6. At this rate, how much would it

Ber [7]

Answer: to make 78 copies it cost 26 dollars.

Step-by-step explanation:

18 copies - 6 dollars

78 copies - x dollars

Hence,

$\displaystyle\\x=\frac{78*6}{18} \\\\x=\frac{26*3*6}{3*6} \\\\x=26 \ dollars$

5 0

2 years ago

Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

Ilya [14]

Answer:

$x^6+3x^3+3+\dfrac{1}{x^3}$

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

$(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}$

4 0

4 years ago