The product od 2 and y is at least 10

Find the radius of a sphere whose surface area is 154cm².with stepss

worty [1.4K]

Answer:

THIS IS YOUR ANSWER:

$area \: of \: spere \: = 4\pi \: r {}^{2} \\ 154cm {}^{2} = 4 \times \frac{22}{7} \times r {}^{2}$

$\frac{154 \times 7}{4 \times 22} = r {}^{2} \\ r {}^{2} = 12.25 \\$

$r = \sqrt{12.25} \\ r = 3.5cm$

✍️HOPE IT HELPS YOU ✍️

7 0

2 years ago

Read 2 more answers

a. It is important to label all your variables and expressions clearly because: it will help you get your equations set up c. it

sveticcg [70]

Answer:

I'm pretty sure it's A. It will help you get your equations set up correctly

Step-by-step explanation:

For anyone needing this answer in the future lol

3 0

3 years ago

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago

Can somebody please help me with this question?

USPshnik [31]

Answer: 6x^2

Step-by-step explanation:

The area of a triangle is 1/2bh

Thus, simply multiply 2x*3x = 6x^2

Hope it helps <3

5 0

3 years ago

Read 2 more answers

What i do to deserve this math love?

earnstyle [38]

Answer:

lifes hard man its whateva

Step-by-step explanation:

4 0

3 years ago