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KonstantinChe [14]
3 years ago
12

Which side lengths form a right triangle?

Mathematics
2 answers:
Stels [109]3 years ago
4 0

Answer:

B) 1, 8, √65

Step-by-step explanation:

For 3 side lengths to form a triangle the sum of two random sides must be bigger than the third side and their differences must be smaller than the third side.

1+8 > √65 because √65 is approximately 8.1

8-1 < √65

inysia [295]3 years ago
3 0

Answer:

B. 1,8,(65)½

Step-by-step explanation:

For the side lengths to form a right triangle they have to obey the Phythagorean Theorem which when paraphrased says " the square of the longer side is equal to the sum of the squares of the other sides"

A . 2² + 15² = 4 + 225 = 229

17² = 289

Not a Phythagorean triple

B. 1² + 8² = 1 + 64 = 65

(65½)² = 65

A Phythagorean triple

C. 2² + (80½)² = 4 + 80 = 84

9² = 81

Not a Phythagorean triple.

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Now find the sum what 2 5/6 and
salantis [7]

Answer:

2 \frac{1}{5} + 1 \frac{5}{6}  =  2 \frac{6}{30}  + 1 \frac{25}{30}  \\  \\  \frac{66}{30}  +  \frac{55}{30}  =  \frac{121}{30}  \\  \\  \\  = 4 \frac{1}{30}

I hope I helped you^_^

3 0
3 years ago
"a pollster wishes to estimate the number of left-handed scientists. how large of a sample is needed in order to be 98% confiden
nadezda [96]
The sample size should be 250.

Our margin of error is 4%, or 0.04.  We use the formula

\text{ME}=z\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

To find the z-score:
Convert 98% to a decimal:  0.98
Subtract from 1:  1-0.98 = 0.02
Divide both sides by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value has a z-score of approximately 2.33.  Using this, our margin of error and our proportion, we have:

0.04=2.33\sqrt{\frac{0.08(1-0.08)}{n}}&#10;\\&#10;\\0.04=2.33\sqrt{\frac{0.08(0.92)}{n}}

Divide both sides by 2.33:
\frac{0.04}{2.33}=\sqrt{\frac{0.08(0.92)}{n}}

Square both sides:
(\frac{0.04}{2.33})^2=\frac{0.08(0.92)}{n}

Multiply both sides by n:
(\frac{0.04}{2.33})^2n=0.08(0.92)

Divide both sides to isolate n:
\frac{0.08(0.92)}{(\frac{0.04}{2.33})^2}=n&#10;\\&#10;\\249.73=n&#10;\\n\approx 250
4 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?
OLEGan [10]

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below  0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

8 0
3 years ago
Find the slope that passes thru (3,5) and (5,8)
Anni [7]
Would it be 3/2 since it’s rise over run with 3 on the x line to 5 and 5 on the y line to 8
3 0
3 years ago
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