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leonid [27]
3 years ago
5

WILL MARK BRAINLIEST ANSWER 2x^2+20x=-38 show work

Mathematics
2 answers:
Mariana [72]3 years ago
8 0
2x^2+20x = -38

2x^2 + 20x + 38 = 0

Divide both sides by 2.

x^2 + 10x + 19 = 0

The quadratic formula works very well here.

Let a = 1, b = 10 and c = 19

x = [-b +- sqrt{b^2 - 4ac}]/(2a)

Plug those values into the formula to find two answers for x.

One is negative and the other positive.

Good luck.
tatuchka [14]3 years ago
5 0
Move 38 to the left side of the equation by adding it to both sides.
<span>2x ^2 + 20x + 38 = 0
</span>Use the quadratic formula to find the solutions.
<span><span>−b±<span>√<span>b^2 − 4 (ac)/</span></span></span>2a
</span>Substitute a = 2, b = 20, and c = 38 into the quadratic formula and solve for x.
<span><span>−20±<span>√<span>20 ^2 − 4⋅(2⋅38)/</span></span></span>2⋅2
</span>Simplify. <span>x = −5±√6
</span>The result can be shown in both exact and approximate form.
<span><span>x = −5±√6
</span></span><span>x ≈ −2.55051025, −7.44948974</span>
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