<span>First, we write an equation to represent that the fencing lengths add up to 568 feet. we call the side of the fence that has three segments of its length x and the side with only two segments y. We write 3x + 2y = 568. We also know that the area of the rectangle is equal to xy, so area = xy. We put y in terms of x using our first equation and find that y = (568 - 3x)/2. We plug this into our area equation and find that area = (568x - 3x^2)/2. To find the maximum we set the derivative equal to 0 and end up with 0 = 284 - 3x. We solve for x and get 94 and 2/3. We then put that into our first equation to find y = 142. So the dimensions that maximize the area are 94 2/3 x 142.</span>
Not sure if this is a question im confused
Answer:
5
Step-by-step explanation:
We have been given that the point 
lies on the curve 
. Q is the point 
. We are asked to find the slope of the secant line 
for 
.
Let us find y-coordinate corresponding to for point P as:
Now, we will use slope formula to find required slope.
Let point 
and point 
.
Using these points in slope formula, we will get:
Therefore, the slope of the line PQ is 5.
Whichever line has the same slope (-1/2) as this line is the answer
Answer: the answer is x=−2
