Answer:
Step-by-step explanation:
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Answer:
13/28
Step-by-step explanation:
Total number of students = 28
Number of students that play basketball = 14
Number of students that play baseball = 19
Number that play neither sport = 5
Number of students playing sports = 28 – 5 = 23
Number of students playing both basketball and baseball = 14 + 19 – 23 = 10
Number of students that play only basketball = 14 – 10 = 4
Number of students that play only baseball = 19 – 10 = 9
Number of students playing basketball or baseball = 4 + 9 = 13
P(a student chosen at random plays basketball or baseball) = 13/28
B = Black
G = Green
Y = Yellow
The total number of ways that he can pick a pic are 3 * 3 * 3 = 27 ways
If he picks Black for the first pic The number of successful ways that he picks two in a row are
B B G
B B Y
B G G
B Y Y Total 4 ways.
If he picks Green first the number of ways are
G G B
G G Y
G B B
G Y Y Total 4 ways
If he picks Yellow first then the number of ways are
Y Y B
Y Y G
Y B B
Y G G And again there are 4 ways
In all we have 12 successes
There are 12/27 chances of picking 2 pics in a row that are the same color.
4/9 <<<< answer
There must be some way to represent this using combinations, but I'm not sure what it is. However this method works.
Answer:
not clear
Step-by-step explanation:
Answer:
going by 0.69 times faster
Step-by-step explanation:
