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Schach [20]
3 years ago
5

In the accompanying diagram of right triangle ABC, altitude ¯¯¯¯¯¯ B D B ⁣ D ¯ is drawn to hypotenuse ¯¯¯¯¯¯

Mathematics
1 answer:
spin [16.1K]3 years ago
8 0

hello i would not know to be honest

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Using the quadratic formula to solve x2 = 5 – x, what are the values of x?
Ivenika [448]

Answer:

x²=5-x

x²+x-5=0

1x²+1x²-5=0

[ax²+bx²+c=0]

∆=b²-4ac

∆=1²-4(-5)(1)=1+20=21

x=(-b±√∆)/2a

x=(-1±√21)/2

meaning:

x=(-1+√21)/2 or x=(-1-√21)/2

4 0
1 year ago
Just want to double check our answer.
bearhunter [10]

0 divided by 2 is 0.

You can use the multiplicative identity property: the product of any number and zero is still zero.

Hope this helped :)

3 0
3 years ago
Someone please help me out:(
gogolik [260]
SAS mmmmmmmmmmmmmmmmmmm
5 0
3 years ago
C - 7 = 12 :((((((((((((((((((((((((((((((((((((((((((((((((((((((
m_a_m_a [10]
C-7=12
C=12+7
Then C= 19
4 0
3 years ago
the length of a rectangle is 5 times as long as its breadth and its area is 1620 m² find area of square whose perimeter is equal
Rus_ich [418]

Answer:

Area of the square is 2916 m^{2}.

Step-by-step explanation:

Let the breadth of the rectangle be represented by w. So that;

length of rectangle = 5w

Area of rectangle = length x breadth

                             = 5w x w

1620 = 5w^{2}

divide through by 5 to have,

w^{2} = 324

w = \sqrt{324}

   = 18

Thus, the breadth of the rectangle is 18 m.

length = 5 w = 5 x 18

           = 90 m

The length of the rectangle is 90 m.

Perimeter of the rectangle = 2(l + w)

                                  = 2( 90 + 18)

                                  = 216 m

Perimeter of a square = 4l

where l is the length of its side.

Given that the perimeters of the rectangle and square are equal, then;

4l = 216

l = \frac{216}{4}

 = 54

length of the side of square is 54 m.

Therefore,

Area of square = l^{2}

                         = 54^{2}

                        = 2916

Area of the square whose perimeter is equal to that of the rectangle is 2916 m^{2}.

6 0
3 years ago
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