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GenaCL600 [577]
3 years ago
11

Where L is the length, in feet, of the pendulum, and π is approximately 22/7. How long must the pendulum be if one complete cycl

e takes 8 seconds?
Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0

Answer:

The simple pendulum should be 15.9 m long.

Step-by-step explanation:

Approximately (for small amplitudes), the period of a simple pendulum is

T = 2*pi * sqrt (L/g), L=length

using pi = 22/7, and g=9.8 m/s^2

8 = 2* 22/7 * sqrt(L/9.8)

solve for L

L = (8*7/(2*22))^2 * 9.8

= 15.874 m

That's quite a long pendulum!

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What is the volume of a rectangular prism with a length of 7 centimeters, a width of 3 centimeters, and a height of 2 centimeter
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Answer:

42cm³

Step-by-step explanation:

7*2*3=42

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In an article about the cost of health care, USA Today reported that a visit to a hospital emergency room has a mean cost of $14
Misha Larkins [42]

Answer: 0.8461

Step-by-step explanation:

Given : \mu=144\ \ ; \sigma=392

Let x be the random variable that represents the cost for the hospital emergency room visit.

We assume that cost for the hospital emergency room visit is normally distributed .

z-score for x=1000 ,

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Using z-value table , we have

P-value =P(x>1000)=P(z>-1.02)=1-P(z≤ -1.02)=1-0.1538642

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3 0
3 years ago
two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)
nadya68 [22]

Answer:

24\sqrt{5}\ yards

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

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So side of one square is 5\sqrt{5}

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

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For second square:

A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}

The perimeter will be:

P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}

So the total fence will be: P1+P2

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3 years ago
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