A) 2 units
B) yes
For A) |5-3|=|2|=2 is the distance from his house to school.
For B)
The distance from his house to school is 2 units; the distance from school to the grocery store is |3--9|=|12|=12. The total distance is 2+12 = 14.
The distance from his house to school is 2 units; the distance from school to the community center is |-4-6|=|-10|=10. The total distance is 2+10 = 12.
The distance from the house to the school to the grocery store is greater.
Answer:
B. School C
Step-by-step explanation:
Having a U-shaped distribution means that the school would have the least number in the middle value/values and the most at the ends.
School C exhibits this trend because it has the most on the outermost ranges (82 for between 1.5 and 2, and 78 for between 3.5 and 4.0), as well as the least number for the middle value (26 for 2.5-3.0
The numbers inbetween also follow the trend, as you can see if you read down the column of school C, the numbers decrease as you get to 2.5-3.0 and increase again to 4.0
Hope this helped!
Answer:
It is Distributed property and False
Step-by-step explanation:
Answer:
There are 9 distinct possible values for q.
Step-by-step explanation:
Let ab be a positive two-digit integer.
- a×b=q=7k from some positive integer k.
- either a or b is 7, since 7 is a prime number and k can be maximum 9.
- assume a=7, then b can be 1,2,3,4,5,6,7,8,9
- b cannot be 0 because a×b=q has to be positive
- if b=7, then a can be 1,2,3,4,5,6,7,8,9
- in both cases there are 9 distinct values for q, which are 7,14,21,28,35,42,49,56,63
<u>Answer:</u>
Among the given numbers, only 2736 and 45 are divisible by both 3 and 9 .
<u>Step-by-step explanation: </u>
We know that an integer is divisible by 3 or 9 iff (if and only if) the sum of it's digits are divisible by 3 or 9 respectively.
Now,
sum of the digits of 1221 = (1 + 2+ 2 + 1)= 6 which is divisible by 3 but not divisible by 9 , hence, 1221 is divisible by 3 but not by 9.
and,
sum of the digits of 2736 = (2+ 7+ 3 + 6)= 18 which is divisible by both 3 and 9 , hence, 2736 is divisible by both 3 and 9.
and,
sum of the digits of 45 = (4 + 5)= 9 which is divisible by both 3 and 9 , hence, 45 is divisible by both 3 and 9.