Answer:
a) 1/27
b) 16
c) 1/8
Step-by-step explanation:
a) 
One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

And now, solving for x = 9 we have:

b) 
This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

c) 
Using the same property we used in a) we have:

And now, solving for z = 16 we have:

Answer:
The diameter is 16.8
Step-by-step explanation:
The diameter is double the radius.
What model? also it would be 1/2 and 1/3
Answer:
11
Step-by-step explanation:
Hello,
Given the original number n.

Multiply the number by 9.

Add 99.

Divide this sum by 9.

Subtract the original number, n, from the quotient.

Thank you.
Answer:
3.14
Step-by-step explanation:
it will go on foreever