All categories

3 years ago

Someone tell me where everyone is going right please !!

Mathematics

2 answers:

Veronika [31]3 years ago

7 0

Answer:

1st drop box: (1) 7.5x - 100 > 79.86 + 5.8x

2nd drop box: (4) x > 105.8

3rd drop box: (4) 106

Step-by-step explanation:

1st drop box:

Revenue (the money you receive) must be greater than the costs (money you spend) to make a profit.

2nd drop box:

Use basic algebra to solve for x:

7.5x - 100 > 79.86 + 5.8x

(subtract 5.8x from both sides)

1.7x - 100 > 79.86

(add 100 to both sides)

1.7x > 179.86

(divide both sides by 1.7)

x > 105.8

3rd drop box:

We already know the solution to the inequality is x > 105.8

Notice how all the answer choices are whole numbers and the inequality sign is "greater than" and not "greater than or equal to".

That means it doesn't include 105.8

And it can't be 105 because 105 is NOT greater than 105.8

So the answer is 106

Hope it helps (●'◡'●)

Allisa [31]3 years ago

4 0

Answer:

hello dude

equation;

7.8x - 100 > 79.86 + 5.8x

and answers are at the photo

HAVE A NİCE DAY

Step-by-step explanation:

greeetings from Turkey ツ

You might be interested in

Convert 99 ounces to pounds and ounces.

Simora [160]

Answer:

6 pounds 3 ounces

Step-by-step explanation:

16 oz in a lb. 16 *6 = 96. Leaving 3 oz left.

8 0

4 years ago

Read 2 more answers

A billboard designer has decided that a sign should have 3 ft margins at the top and bottom and 5 ft margins on the left and rig

elixir [45]

Answer:

The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is $9000 ft^2$ then $9000=xy$

Step-by-step explanation:

• The total width of billboard is [x]. Therefore the width of printed area will be (x-10) by excluding margin of left and right side.

• The total height of billboard is [y]. Therefore the height of printed area will be [(y-6)] by excluding the margin of top and bottom from the total height.

• To find the printed area of billboard calculations are given below:

$& 9000=xy$

$& y=\frac{9000}{x} \\ & A=(x-10)(y-6) \\ & A=xy-6x-10y+60 \\ & A=x\left( \frac{9000}{x} \right)-6x-10\left( \frac{9000}{x} \right)+60 \\ & A=9060-6x-\frac{9000}{x} \\$

On taking the first order derivative of A

$A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)$

$& \left( \frac{90000}{{{x}^{2}}} \right)-6=0 \\ & 6{{x}^{2}}=90000 \\ & x=\sqrt{15000} \\ & y=\frac{9000}{x}=\frac{90000}{\sqrt{15000}}=10\sqrt{150} \\$