the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
Width of the room = 5 meters
Step-by-step explanation:
the rectangular living room is calculated as length * width
The area is given to be equal to 40 sq. meters (area = 40 sq. meters)
Let the width = x meters
Length = X+3 meters
Area = Length * Width
40 = X * (X+3)
40 = X^2 + 3X
We solve this quadratic equation
So x = 5 or x= -8
Width cannot be negative, so we reject x =-8
So x = 5 is the answer
Answer:
they would have to do 2 chores each. they will each have eight dollars
Answer:
(-6,5)
Step-by-step explanation:
Answer: 2(3x^2-5x-1) or 6x^2-10x-2
Step-by-step explanation: combine like terms, and then factor by grouping :)
