Answer:
Segment JK is a chord in circle H
Line LM is a secant to circle H
Step-by-step explanation:
* Lets revise some definition in the circle
- The radius of the circle is a line segment drawn from the center of
the circle to a point on the circumference of the circle
- The chord of a circle is a line segment whose endpoints lie on the
circumference of the circle
- The secant is a line intersect the circle in two points
- The tangent is a line touch or intersect the circle in one point
* Now lets solve the problem
- In circle H
∵ JK is a segment in circle H
∵ Point J lies on the circumference of circle H
∵ Point K lies on the circumference of circle H
∴ Segment JK is a chord in circle H
∵ LM is a line
∵ LM intersect circle H in two points L and M
∴ Line LM is a secant to circle H
9+12=m or 9+12=21
this is because when we start with m-9=12 we know that m is supposed to be the sum of 9 and 12.
if we check our work we will see this
9+12=21
9+12=21
m-9=12
21-9=12
Answer:
2.a) 3 ( x - 1 ) = 5x - 6 (Because the sides of a square are always equal)
b) 3 ( x - 1 ) = 5x - 6
=> 3x - 3 = 5x - 6
=> 3x - 5x = -6 + 3 (Law of transposition)
=> -2x = -3
=> -x = -3/2
=> -x = -1.5
=> x = 1.5 (By cancelling out the negative sign from both the sides)
c) 3(x-1) = 3 (1.5 - 1)
=> 3 (0.5)
=> 3 * 0.5 = 1.5
Both the angles are 1.5 because they are equal
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Thank You!