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NeTakaya
3 years ago
9

A stock with a beta greater than 1.0 has returns that are​ ________ volatile than the​ market, and a stock with a beta of less t

han 1.0 exhibits returns which are​ ________ volatile than those of the market portfolio.
Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0

Answer:

more, less

Step-by-step explanation:

Beta is a measure of volatility. It is used in calculating the cost of equity using the CAPM (Capital Asset Pricing Model formula).

A beta greater than 1 signifies that the returns from an investment is expected to be higher than the returns from the general market as the risk inherent in that investment is higher.

Similar to the economic concepts of elasticity, a change in one variable (in this case, beta of the stock) setting about a greater than proportionate change in another variable (returns from the stock).

Thus, a stock with beta of less than 1, will be less volatile than the market.

I hope this helps you understand the concept better.

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10. simplify the rational expression by rationalizing the denominator.( 1 point ) 4√150/√189x
ddd [48]
Rationalizing the denominator, simply means "getting rid of that pesky root at the bottom", and we do so by simply multiplying it by something to take it out, of course, we multiply the bottom, we have to also multiply the top,

\bf \cfrac{4\sqrt{150}}{\sqrt{189x}}\cdot \cfrac{\sqrt{189x}}{\sqrt{189x}}\implies \cfrac{4\sqrt{150}\sqrt{189x}}{(\sqrt{189x})^2}\implies \cfrac{4\sqrt{(150)({189x})}}{189x}

\bf \cfrac{4\sqrt{28350x}}{189x}\qquad 
\begin{cases}
28350=2\cdot 3\cdot 3\cdot 3\cdot 3\cdot 5\cdot 5\cdot 7\\
\qquad 2\cdot 3^2\cdot 3^2\cdot 5^2\cdot 7\\
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\qquad 2\cdot (3^2\cdot 5)^2\cdot 7\\
\qquad 2\cdot (45)^2\cdot 7\\
\qquad 14\cdot 45^2
\end{cases}\implies \cfrac{4\sqrt{14\cdot 45^2}}{189x}
\\\\\\
\cfrac{4\cdot 45\sqrt{14}}{189}\implies \cfrac{180\sqrt{14}}{189x}\implies \cfrac{20\sqrt{14}}{21x}
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Hello may i please have help with this question
Pani-rosa [81]

Answer:

x=√139-3, x=-√139-3

Step-by-step explanation:

to complete the square, you first move the constant to the other side of the equation-its already done for you!

now, you find the perfect square trinomial. You divide the b value by 2, then square it: 6/2=3, 3^2=9.

What you do to one side has to be done with the other.

x^2+6x+9=130+9

now you can factor the square:

(x+3)^2=139

squareroot both sides:

x+3=√139

x+3=-√139

now subtract both sides by 3

x=√139-3

x=-√139-3

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