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NikAS [45]
3 years ago
6

A shrew is a tiny mouse like mammal that can eat several times it's weight each day a three ounce shrew can eat one pound of ins

ects and worms if you ate like a shrew and weighed 80 pounds how much would you eat
Mathematics
1 answer:
otez555 [7]3 years ago
6 0

So since he eats a pound of food when he weighs 3 ounces he eats about 5 and 1/3 times more than his own size. That means if we ate like shrews and we weighed 80 pounds we would eat about 426 pounds of food.

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Rewrite 23/25 and 9/10 so they have a common denominator
Kazeer [188]
Well you have to have the common at 50 because that it so multiply23/25 by 2 and 9/10 by 5 so 45/50 and 46/50
3 0
3 years ago
Steps factoring polynomials using gcf for 9x²+9x
Molodets [167]

Answer:

Step-by-step explanation:

Step 1: Identify the GCF of the polynomial.

Step 2: Divide the GCF out of every term of the polynomial. ...

Step 1: Identify the GCF of the polynomial. ...

Step 2: Divide the GCF out of every term of the polynomial.

Step 1: Identify the GCF of the polynomial. ...

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6 0
3 years ago
A square piece of cardboard has sides that are 7/12 meter long. What is the carb words perimeter
gavmur [86]

Since it’s a square all sides are even. Meaning you multiply 7/12 by 4. Giving you 7/3 or 2 ⅓. Hope this helps!

6 0
3 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
Write an expression which solves for the radius of an object having the circumference of 30 feet
Likurg_2 [28]
circumference=30ft.\\\\circumference=2\pi r\ (r-radius)\\\\2\pi r=30\ \ \ \ /:2\pi\\\\r=\frac{30}{2\pi}\\\\r=\frac{15}{\pi}\ (ft)\\\\\frac{15}{\pi}\approx\frac{15}{3.14}\approx4.78\ (ft)
8 0
3 years ago
Read 2 more answers
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