Answer:
He shpt 2 under par for both rounds 3 and 4
Step-by-step explanation:
-4 + 2 = -2
-8 - (-2) = -4
-4 / 2 = -2
56
cos(E)=0.8
cos(E)=adjacent/hypotenuse
Using a common pythagorean triple, we can find that side GE is 30 (18^2+24^2=30^2)
Then we just get cos(E)=24/30, which is 0.8
120 · b = 312 or 120b = 312
It is 2πrh + 2π
