Answer:
see below
Step-by-step explanation:
Use the distributive property:
(y^2 +3y +7)(8y^2 +y +1)
= y^2(8y^2 +y +1) +3y(8y^2 +y +1) +7(8y^2 +y +1)
= 8y^4 +y^3 +y^2 + 24y^3 +3y^2 +3y + 56y^2 +7y +7
= 8y^4 +y^3(1 +24) +y^2(1 +3 +56) +y(3 +7) +7
= 8y^4 +25y^3 +60y^2 +10y +7 . . . . . matches the last choice
Given:
The three vertices of the parallelogram are (-3,9), (0,-3), (6,-6).
To find:
The fourth vertex of the parallelogram.
Solution:
Consider the three vertices of the parallelogram are A(-3,9), B(0,-3), C(6,-6).
Let D(a,b) be the fourth vertex.
Midpoint formula:
We know that the diagonals of a parallelogram bisect each other. So, the midpoints of both diagonals are same.
Midpoint of AC = Midpoint BD
On comparing both sides, we get
And,
Therefore, the fourth vertex of the parallelogram is (3,6).
Answer:
225
I used
www.symbolab.com
to help me solve this
