Answer:
r^12 no r^6
Step-by-step explanation:
I was wrong it is r^6 r−9(−3) r−9+3=r−6
Answer:
y = -2·x^2 - 5·x - 18
y = -2·(x^2 + 10·x + 36)
y = -2·(x^2 + 10·x + 36)
y = -2·(x - (-5 - √11·i))·(x - (-5 + √11·i))
Maybe there is a typo in the original question, because there is no factorisation in the real numbers.
Because the question is " find the minimum value of y" the coefficient before x^2 must be a positive number. so it could be
y = 2·x^2 - 5·x - 18
Can you check this out?
I'm pretty sure it's 3,000,000, "Basically, if the power is positive, you move the decimal point in the integer that many places to the right ex:
3.14 x 10 ^ 3 would be 3140.
If the power is negative, you move the decimal point to the left ex:
3.14 x 10 ^ -3 would be 0.000314" according to Yahoo
Answer:
24 square units
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the blue point is located at the origin.
Therefore, coordinates of the vertices of the given triangle ABC will be,
A(2, 1), B(2, -1) and C(3, -1)
Rule for the dilation of a point (x, y) by a scale factor 'k' will be,
(x, y) → (kx, ky)
By applying this rule, coordinates of the image points of the vertices will be,
A(2, 1) → A'(2k, k)
→ A'(6, 3) for (k = 3)
B(2, -1) → B'(6, -3)
C(3, -1) →C'(9, -3)
