Given:
x, y and z are integers.
To prove:
If 
is even, then at least one of x, y or z is even.
Solution:
We know that,
Product of two odd integers is always odd. ...(i)
Difference of two odd integers is always even. ...(ii)
Sum of an even integer and an odd integer is odd. ...(iii)
Let as assume x, y and z all are odd, then is even.
is always odd. [Using (i)]
is always odd. [Using (i)]
is always even. [Using (ii)]
is always odd. [Using (iii)]
is always odd.
So, out assumption is incorrect.
Thus, at least one of x, y or z is even.
Hence proved.
Answer:
option 3
Step-by-step explanation:
Answer:
The inequality is 
Step-by-step explanation:
<u><em>The question is incomplete so the complete question is attached below:</em></u>
Now, to write an inequality that can be used to find 
, the number of weeks after starting his collection when Lawrence will have more than 750 baseball cards in his collection.
Let the number of weeks be 
Number of cards Lawrence purchases each week = 25.
Number of cards Lawrence's father gave him = 200.
Total number of cards Lawrence will have more than in his collection = 750.
Now, to write an inequality that can be used to get the number of weeks after starting his collection when Lawrence will have more than 750 baseball cards in his collection:
Therefore, the inequality is
#54 is wrong is A is says full to shaded
Answer:
A 19 yard gain
Step-by-step explanation:
Simple the question answers itself
