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kogti [31]
3 years ago
11

Find the limit as h goes to 0 of the quotient of the quantity 5 times the square of the quantity x plus h, minus 2 minus the qua

ntity 5 times x squared minus 2, and h.
5x^2 + h^2 + 7

10x

3x^2 – 2

10x – 2

Mathematics
1 answer:
umka21 [38]3 years ago
5 0
Expand
\lim_{h \to 0} \frac{5(x^2+2hx+h^2)-2)-5x^2+2}{h}

\lim_{h \to 0} \frac{5x^2+10hx+5h^2-2-5x^2+2}{h}

\lim_{h \to 0} \frac{10hx+5h^2}{h}

\lim_{h \to 0} 10x+5h
say h=0 so
10x

answer is 2nd one
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