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nekit [7.7K]
3 years ago
12

1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h

Mathematics
1 answer:
alina1380 [7]3 years ago
4 0

Answer:(g,h)=(-2,2)

Step-by-step explanation:

Given

Midpoint is (-2,3)

Endpoints are G(g,4) and H(-2,h)

Mid point of any two point is given by

x=\frac{x_1+x_2}{2}

and y=\frac{y_1+y_2}{2}

So,-2=\frac{g+(-2)}{2}

-4=g-2

g=-2

Also

3=\frac{4+h}{2}

6=4+h

h=2

Therefore (g,h)=(-2,2)

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X^2+ 3 has a value of 28. What term in the sequence has a value of 28?
VikaD [51]

Answer:

5th term

Step-by-step explanation:

x^2 +3 = 28

Subtract 3 from each side

x^2+3-3 =28-3

x^2 = 25

Take the square root of each side

sqrt(x^2) = sqrt(25)

x = 5

(x could be -5, but there are not usually negative terms in a sequence)

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The radius of a circle is 5 inches. What is the circle's diameter?
Anastasy [175]

Answer:

10 inches

Step-by-step explanation:

Simply,multiply radius by 2...

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3 years ago
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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
2 years ago
I need Help!!!<br><br><br>(Question is attached)
katrin2010 [14]

Answer:

SEE BELOW

Step-by-step explanation:

1 - 12000 ft

2 - 10 minutes

3 - The third segment in he graph is not as steep as the first segment because the flight took more time to lose altitude than the time taken to gain altitude.

<em>Hope it helped</em>

3 0
2 years ago
What is the value of x?
olga_2 [115]

Answer:

<x = 20°

Step-by-step explanation:

<x = 1/2(arc UT - arc SV)

<x = 1/2(65° - 25°)

<x = 1/2 (40°)

<x = 20°

3 0
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