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DerKrebs [107]
3 years ago
7

The following two-way frequency table shows information collected from a survey of

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

0.62

Step-by-step explanation:

In the picture attached, the table is shown.

We want to find the probability that a student uses the Internet, given that he or she is in eighth  grade. Mathematically:

P(Internet | eighth  grade) = P(Internet ∩ eighth  grade)/P(eighth  grade)

P(Internet | eighth  grade) = (8/28)/(13/28) = 8/13 = 0.62

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A community center rents their hall for special events. They charge a fixed fee of $200 plus an hourly fee of $22.50. Lin has $3
Karo-lina-s [1.5K]

Answer:

No, 6 hours would cost $335, 35 over her limit of $300.

Step-by-step explanation:

she has to pay $200 plus 22.50 for every hour she rents. So, if she rents for 6 hours, she has to pay $200 + 6(22.50) or $200 + 135=335. She only has $300 so she can’t afford the event.

3 0
2 years ago
X+ 2 / X + 3 =5 plz give me and<br><br><br><br>​
Anna35 [415]

Answer:

The answer is x = -13/4

Step-by-step explanation:

-13/4 + 2  /  -13/4 +3 = 5

5 0
2 years ago
Does anyone know how to solve with elimination and if so can you do this problem
Kryger [21]
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3 0
3 years ago
The mean age of 5 people in a room is 32 years. A person enters the room. The mean age is now 34. What is the age of the person
nikdorinn [45]
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8 0
3 years ago
Carlos has at most $40 to spend on food for a barbeque. He wants to buy hot dogs and hamburgers and then
poizon [28]

Answer:

$8.50

Step-by-step explanation:

I don't know what Alls are, but if Carlos insists, we can calculate how much he can spend on Alls with the expression:

($31.50) + r \leq $40

This says the sum of what Carlos has already spent (hot dogs and hamburgers) plus the amount he spends on Alls (rolls?), r,  must be equal to or less than the $40 he has allowed himself to spend.

($31.50) + r \leq $40

r  \leq $40 - $31.50

r \leq $8.50

3 0
2 years ago
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