All categories

3 years ago

Which property is illustrated by the following statement? (3z)xy=3(zy)y

Mathematics

2 answers:

Nataliya [291]3 years ago

7 0

The property illustrated is the Associative property of multiplication

Alborosie3 years ago

3 0

Answer:

Associative property of multiplication

Step-by-step explanation:

$(3z)xy=3(zx)y$

Associative property of multiplication is grouping of terms

$a(bc)= (ab)c$

Commutative property of multiplication is multiplying the terms in any order

$abc= acb$

Inverse property of multiplication states that the product of a term and its inverse is 1

the inverse of 'a' is $\frac{1}{a}$

Commutative property of addition is adding the terms in any order

$a+b= b+a$

$(3z)xy=3(zx)y$

Here the group of terms in multiplication is changes. So it represents associative property of multiplication

You might be interested in

Work out the circumference of this circle take pie to be 3.142 and give your answer to 1 decimal place R=9m

olasank [31]

Answer:

C = 56.6

Step-by-step explanation:

Circumference Formula: C = 2πr

Simply plug in r into your formula

C = 2π(9)

C = 18π or 56.556

3 0

3 years ago

Julia lined up the interior angles of the triangle along the line below. What is the answer?

pshichka [43]

30 degrees is your answer.

6 0

3 years ago

Read 2 more answers

Which one is equivalent Look at the pic

Paha777 [63]

(3/5)³

=(3³)/(5³)

=27/125

---------------

As:

3*3*3=27

And:

5*5*5=125

6 0

3 years ago

Read 2 more answers

On n − {1}, the relation r given by a r b iff the prime factorizations of a and b have the same number of 2's. for example, 48 r

grin007 [14]

Yes the answer to the question is 100rx

5 0

3 years ago

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

3 years ago