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4 years ago

7

Suppose that to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77, 71, 77, and 67 i

n your first 4 games what is the highest score you can shoot in your 5th game and still make the team?
A. 76
B. 78
C. 79
D. 80

1 answer:

strojnjashka [21]4 years ago

4 0

The answer is letter B. 78

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The sequence 2, 3, 5, 6, 7, 10, 11, $\ldots$ contains all the positive integers from least to greatest that are neither squares

mariarad [96]

Answer:

1041

Step-by-step explanation:

Among the numbers 1–1000, there are 31 squares, so the sequence will extend to at least 1031. In those added numbers, there is another square (1024), so the sequence must extend to at least 1032.

There are 7 more numbers that are cubes, but not squares, so the sequence must extend to at least 1039.

And there are 2 additional numbers that are 5th powers that are not squares or cubes. Compensating for the removal of these numbers extends the end of the sequence to 1041.

There are no numbers in this range that are both cubes and 5th powers and that have not already been accounted for. (The only 15th power is 1.)

Hence, the 1000th number in the sequence is 1041.

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This result is verified by a computer program that listed the numbers.

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4 years ago

Answer 8 and 9 for 10+ points

castortr0y [4]

Answer:

question 8 : it is equal to 0

Question 9 : 4+5 $\sqrt{2}$

Step-by-step explanation:

= $\sqrt{7} -\sqrt{28}\\2\sqrt{7} - \sqrt{4x7}\\2\sqrt{7} - 2\sqrt{7}\\0\\\sqrt{2} (5+\sqrt{8})\\5\sqrt{2} + \sqrt{2*8}\\5\sqrt{2} + 4\\4 + 5\sqrt{2}$

4 0

3 years ago

What is -5.1982569 to the nearest hundredths

s2008m [1.1K]

- 5 . 1 9 8 2
|
hundredths place

so -5.2 or -5.20 for sig. fig.

5 0

3 years ago

Read 2 more answers

A running shoe store mounts a new promotional campaign. Purchasers of new shoes may, if dissatisfied for any reason, return them

Vitek1552 [10]

Answer:

a

$P(K = k ) = \ ^nC_x * p^k * (1-p)^{n-k}$

Here k is the random number of number of pairs of shoes that will be returned for refund, which can be k = 0,1 ,2,3,4 ..., 120

b

The mean is $E(K) = np = 13.2$

The standard deviation is $\sigma = 3.43$

c

The mean is $E(C) = E(105 K) = 1386$

The standard deviation is $\sigma = 381.48$

Step-by-step explanation:

From the question we are told that

The cost to dealer for each refund is $C = \$105$

The probability that a shoe will refunded is $P(x) = 0.11$

The number of shoes purchased is n = 120 pairs

Generally the probability distribution of the number of pairs of shoes that will be returned for refunds is

$P(K = k ) = \ ^nC_x * p^k * (1-p)^{n-k}$

Here k is the random number of number of pairs of shoes that will be returned for refund, which can be k = 0,1 ,2,3,4 ..., 120

Generally the mean is mathematically represented as

$E(K) = np = 120 * 0.11$

=> $E(K) = np = 13.2$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{ n* p (1-p)}$

=> $\sigma = \sqrt{ 120* 0.11 (1-0.11)}$

=> $\sigma = 3.43$

Generally the total refund cost is mathematically represented as

$C = 105 K$

Here K denotes the number of shoes returned

Generally the mean of the total refund cost is mathematically represented as

$E(C) = E(105 K) = 105 E(K)$

=> $E(C) = E(105 K) = 105 * 13.2$

=> $E(C) = E(105 K) = 1386$

Generally the variance of the total refund cost is mathematically represented as

$Var(K) = 105^2 * E(K)$

=> $Var(K) = 105^2 * 13.2$

=> $Var(K) = 145530$

=> $\sigma = \sqrt{145530 }$

=> $\sigma = 381.48$

7 0

3 years ago

Solve for given time

xxMikexx [17]

Answer:

let P=36000

R=12%

T=2years

Step-by-step explanation:

no.of bacteria after 2=P(1+R/100)^t

=36000(1+12/100)²=45158.4

3 0

3 years ago