B. 4.5=2m+g
f. 9.25=3m+2g
1.25=m
sub
b. 4.5=2(1.25)+g
f. 9.25=3(1.25)+2g
b. 4.5=2.5+g
f. 9.25=3.75+2g
minus 2.5 from both sides on the b. equaion and minus 3.75 from both sides on the f. equation
b. 2=g
f. 5.5=2g
divide both sides of f. equation by 2
b. 2=g
f. 2.75=g
2.75-2=0.75
finn paied $0.75 more for a bag of grapes
Answer:
(x-2,y-4)
Step-by-step explanation:
Here, we want to calculate the rule for the translation
From the question, we can see that the new image was just formed as a movement of the old image by some particular units
The x-axis was move sideways while the y-axis was moved further down
The number of units is thus;
Y from 12 to 8
A movement of -4
For the x-axis
we have a movement of two units toward the left
So the rule is;
(x,y) to (x-2, y-4)
Y+2=-3/5(x+5)
y+2=-3/5x-3
y+5=-3/5x
Hope this helps :)
22,69,210
22+1=23x3=69
69+1=70x3=210
Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws