Answer:
Third option: 12x^2+8x+25
Step-by-step explanation:
s1=8x^2
s2=4x^2+15
s3=8x+10
Total perimeter of the pool edge: P
P=s1+s2+s3
Replacing s1, s2 and s3 in the formula above:
P=(8x^2)+(4x^2+15)+(8x+10)
P=8x^2+4x^2+15+8x+10
Adding like terms:
P=12x^2+8x+25
Answer:
the answer is D
Step-by-step explanation:
tl;dr Answer is C
Here we will have to calculate 3 different areas separately.
When calculating the area of the triangle we will use the formula
A = (h*b)/2
A = Area
h = height
b = base
To find the height we do X - Z
23 - 15 = 8 ft
To find the base we do Y - W
19 - 13 = 6 ft
Using the formula above we can now solve for A
A = (8*6)/2
A = (48)/2
A = 24 sq ft
Now we solve the two rectangles using the formula
A = wl
w = width
l = length
We will calculate the area of the left most rectangle first.
We know the length of the rectangle because it's Y - W and we are given the width of the triangle.
w = 15 ft
l = 6 ft
A = 15*6
A = 90 sq ft
Second Rectangle has the width of X and length of W
w = 23 ft
l = 13 ft
A = 23 * 13
A = 299 sq ft
Now we add all the areas to give us the total area of the warehouse.
24 + 90 + 299 = 413 sq ft
Therefore, the answer is C
Answer:
its cut off Step-by-step explanation:
its cut off dude
