First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Step-by-step explanation:
=9.8-6.4n
just add them together as easy as that
Answer:
The answer is choice 2 and 3, that is "The quotient has a final decimal and the whole number is less than 11".
Step-by-step explanation:
The product of a ratio: amount (r) over other(s) (variance from 0) becomes mandatory to note this quotient and in the following case Thus q is = 0.0882352941.
It wasn't a repeating decimal, however a final decimal, so it's got an end.
Its quotient may be less than 11 in total.
Numbers of W = {0,1,2, ...} and 0 < 11 are provided for this entire series of data therefore It's real .
What’s is this I don’t know
Answer:
Step-by-step explanation:
