Check the picture below.
so the volume will simply be the area of the hexagonal face times the height.
![\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\stackrel{\qquad degrees}{\cot\left( \frac{180}{n} \right)}~~ \begin{cases} n=\stackrel{number~of}{sides}\\ s=\stackrel{length~of}{side}\\[-0.5em] \hrulefill\\ n=6\\ s=12 \end{cases}\implies A=\cfrac{1}{4}(6)(12)^2\cot\left( \frac{180}{6} \right) \\\\\\ A=216\cot(30^o)\implies A=216\sqrt{3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the hexagon}}{(216\sqrt{3})}~~\stackrel{height}{(10)}\implies 2160\sqrt{3}~~\approx ~~3741.2~cm^3](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B4%7Dns%5E2%5Cstackrel%7B%5Cqquad%20degrees%7D%7B%5Ccot%5Cleft%28%20%5Cfrac%7B180%7D%7Bn%7D%20%5Cright%29%7D~~%20%5Cbegin%7Bcases%7D%20n%3D%5Cstackrel%7Bnumber~of%7D%7Bsides%7D%5C%5C%20s%3D%5Cstackrel%7Blength~of%7D%7Bside%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20n%3D6%5C%5C%20s%3D12%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B4%7D%286%29%2812%29%5E2%5Ccot%5Cleft%28%20%5Cfrac%7B180%7D%7B6%7D%20%5Cright%29%20%5C%5C%5C%5C%5C%5C%20A%3D216%5Ccot%2830%5Eo%29%5Cimplies%20A%3D216%5Csqrt%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20hexagon%7D%7D%7B%28216%5Csqrt%7B3%7D%29%7D~~%5Cstackrel%7Bheight%7D%7B%2810%29%7D%5Cimplies%202160%5Csqrt%7B3%7D~~%5Capprox%20~~3741.2~cm%5E3)
Angle e = x angle d = 5x supplementary means they add up to 180
x + 5x =180
6x = 180
6x/6 = 180/6
x = 30
so angle e = 30 and angle d = 5(30) = 150
Answer:
$12.56
Step-by-step explanation:
$50.24 divided by the 4 friends = $12.56
I divided the total cost by the amount of friends who went to the museum and so I did $50.24 divided by the 4 friends = $12.56.
1/8 is the answer to the problem
Answer:
0.7 = 70%.
Step-by-step explanation:
There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:
C(5,2) = 5!(3!*2!) = 5*4/2 = 10
To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:
There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:
C(3,2) = 3!/2! = 3
So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7
Then, the probability is 7 / 10 = 0.7 = 70%.
