Answer:
the quadratic formula is ax^2 + bx + c", if the first one is expanded out I will be 6x^2+8x+27 so that's the answer
Im pretty sure its x less-than-or-equal-to 3
Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
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Answer:
AE = CE = 23; BE = DE = 20
Step-by-step explanation:
Put the values of the variables in their place and do the arithmetic.
AE = 2u+5 = 2(9) +5 = 23
BE = 6v-1 = 6(3.5) -1 = 20
CE = 3u-4 = 3(9) -4 = 23
DE = 8v-8 = 8(3.5) -8 = 20
The diagonals cross at their midpoints, so the quadrilateral is a parallelogram.
Answer:
where am i supposed to find the x if you haven't given the equation for the sum
Step-by-step explanation:
