<span>If the point(4,-1) i a point on the graph of f, then f(4)= -1
hope it helps</span>
Answer: C) Qualitative
The response isn't a numeric value, but rather a name instead. So that's why we have qualitative data here. Specifically, it is nomimal as it deals with names or labels. The data is not ordinal as we cannot sort the labels.
Answer:
v_0(initial velocity) v_f(final velocity) a(acceleration)
v_0=70 km/h v_f= 0 km/h( rest)
Kinematics equation is a=(v_f-v-0)/time
a=(0-70)/(7/3600) which means it decelerates at -36000 km/h
This number is humongous; I would advise you to re-check the problem and see if the the time it takes is 7 hours rather than 7 seconds. Notice that I put the time as 7/3600 because it is 7 seconds which should be converted to hours.
<span>Part
A:
a) What do the x-intercepts and maximum value of the graph represent?
The x-intercepts are the distances at which the ball is on the ground.
First, at x = 0, that is when the ball is kicked; second, at x = 30, when the ball falls (return) to the ground.
b) What are the intervals where the function is increasing and decreasing,
and what do they represent about the distance and height? (6 points)
The function is increasing in the interval (0, 15) and is decreasing in the interval (15,30)
The increasing interval (0,15) is the horizontal distance from the point the the ball was kicked until it reached its highest altitude, this is where the ball was going upward.
The decreasing interval (15,30) is the horizontal distance from the point where the ball reached its highest altitude until it landed on the ground, this is where the ball was falling down.
Part B: What is an approximate average rate of change of the graph from x
= 22 to x = 26, and what does this rate represent
On the graph you can read that at x = 22, f(x) ≈ 12, and at x = 26 f(x) ≈ 7.
So, an approximate rate of change from x = 22 to x = 26 is given by the equation below:
change on f(x) 7 - 12
average rate of change = --------------------- = ----------- = -5/4
change of x 26 - 22
That rate represents that the ball fell about 5 ft per 4 ft in that interval.
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