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marissa [1.9K]
4 years ago
6

Helppppppppppppp with 4,5,6

Mathematics
1 answer:
kondor19780726 [428]4 years ago
3 0
4.112/15=7.466666...
the answer is 8.
5.the answer is 7.
6.2*6-9=3.

Merry Christmas <span />
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Find x pls help me this is due soon
seraphim [82]

Answer:

x=35

hope it helps..........

8 0
3 years ago
Please Help I Don't Undertand.
frozen [14]

If triangles AMN and ABC are similar, then

AM/AB = AN/AC

or

AM/(AM + MB) = AN/(AN + NC)

Check if this is true:

AM/AB = 21/(21 + 9) = 21/30 = 7/10

AN/AC = 14/(14 + 6) = 14/20 = 7/10

The angle at vertex A is common to both of the triangles.

Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.

4 0
2 years ago
At the beginning of an experiment, the temperature of a solution was 48°C. During a 6-hour
ExtremeBDS [4]

9514 1404 393

Answer:

  • -2.2(6) +1.8(4) . . . temperature change
  • 42 °C

Step-by-step explanation:

At the end of the first 6 hours, the temperature change was ...

  (-2.2 K/h)(6 h) = -13.2 K

The change in the next 4 hours was ...

  (1.8 K/h)(4 h) = 7.2 K

Then the total change over the 10-hour period was ...

  (-2.2)(6) +(1.8)(4) . . . . . expression for temperature change

This evaluates to -13.2 +7.2 = -6.

__

The final temperature is the sum of the initial temperature and the temperature change:

  final temperature = 48 °C -6 °C = 42 °C

_____

<em>Additional comment</em>

When temperature is measured on the Celsius scale, a change of 1 degree is called a kelvin (K).

8 0
3 years ago
Simplify the following​
den301095 [7]

Answer:

1) 11\sqrt{3}

2) 2\sqrt{2}

3) 20\sqrt{3}  + 15\sqrt{2}

4) 53 + 12\sqrt{10}

5) -2

6) 7\sqrt{2}  - 5\sqrt{3}

Step-by-step explanation:

1) 2\sqrt{12} + 3\sqrt{48} - \sqrt{75}

=(2 × 2\sqrt{3} )+ (3 × 4\sqrt{3}) - 5\sqrt{3}

= 4\sqrt{3} + 12\sqrt{3} - 5\sqrt{3}

= 11\sqrt{3}

2) 4\sqrt{8} -2\sqrt{98} + \sqrt{128}

= (4 × 2\sqrt{2}) - (2 × 7\sqrt{2}) + 8\sqrt{2}

= 8\sqrt{2} - 14\sqrt{2} +8\sqrt{2}

= 2\sqrt{2}

3) 5\sqrt{12\\} - 3\sqrt{18} + 4 \sqrt{72}  +2\sqrt{75}

= 5× 2\sqrt{3} - 3×3\sqrt{2} + 4×6\sqrt{2} + 2×5\sqrt{3}

= 10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}

= 20\sqrt{3}  + 15\sqrt{2}

4) (2\sqrt{2}  + 3\sqrt{5} )^{2}

= 8 + 12\sqrt{10} + 45

= 53 + 12\sqrt{10}

5) (1+\sqrt{3} ) (1-\sqrt{3} )

= 1 - 3

= -2

6) (2\sqrt{6} -1) (\sqrt{3} -\sqrt{2}  )

= 2\sqrt{18}-2\sqrt{12}  -\sqrt{3}  +\sqrt{2}

= 2×3\sqrt{2} - 2×2\sqrt{3} - \sqrt{3} + \sqrt{2}

= 6\sqrt{2}  - 4\sqrt{3} -\sqrt{3} +\sqrt{2}

= 7\sqrt{2}  - 5\sqrt{3}

Hope the working out is clear and will help you. :)

5 0
3 years ago
Read 2 more answers
How do you find the surface area of a cube
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Find the surface area of one side and multiply it by 6
6 0
3 years ago
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