Write the expression in algebraic form. [hint: sketch a right triangle.] tan(arcsec(x/3))

1 answer:

6 0

Sketch a right triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x” and assigning angle “a” as the angle between A and H. Using Pythagorean theorem, you will get “square root of x-squared minus 9” as the opposite side (O). Using SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) = x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.

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Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.