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Mariana [72]
3 years ago
8

A ceramic vase that cost an antique store $5 was marked $20. What is the percentage markup on the price of the ceramic vase?

Mathematics
1 answer:
Anika [276]3 years ago
8 0
The answer would be 75%%%%
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A bird species in danger of extinction has a population that is decreasing exponentially (A = A0e^kt). Five years ago, the popul
Natalija [7]

Answer:

It'll take approximately 34 years from today.

Step-by-step explanation:

in order to solve this problem we first need to find the rate of change, "k", to do that we will use the given information where the population was 1400 five years ago and its now 1000. Applying this data to the equation gives us:

A = A_0*e^{k*t}\\1000 = 1400*e^{5*k}\\1400*e^{5*k} = 1000\\e^{5*k} = \frac{1000}{1400}\\ln(e^{5*k}) = ln(\frac{1000}{1400})\\5*k = ln(1000) - ln(1400) \\k = \frac{ln(1000) - ln(1400)}{5} = -0.06729

We now know the value for "k", we can estimate how many years it will take for the bird population to dip below 100. We have:

100 = 1000*e^{-0.06729*t}\\e^{-0.06729*t} = \frac{100}{1000}\\ln(e^{-0.06729*t} = \frac{1}{10}\\-0.06729*t = ln(0.1)\\t = -\frac{ln(0.1)}{0.06729} = 34.22

It'll take approximately 34 years from today.

8 0
4 years ago
One student can paint a wall and 12 minutes another student can paint the same more than 24 minutes working together how long wi
iren2701 [21]

Answer:

It would take them 6 minutes to paint the wall and 12 to paint the other half : 18 minutes

Step-by-step explanation:

Say that the student who can paint a wall in 12 minutes is painting half of the wall it would take them 6 minutes

As the other student who can paint the same wall in 24 minutes also paints half of a wall it would take that person 12 minutes.

8 0
3 years ago
Read 2 more answers
Which of the following is a coefficient in -11x + 9m + 7?
galina1969 [7]
11 and 9 are coefficient
Because they both have a variable to them.
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Write an equation what number plus 8 equals 12?
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8 + 4 = 12 is the equation.
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Y+6=-1/2(x-6) or simplified to y=-1/2x-3 
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3 years ago
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