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Mariana [72]
3 years ago
8

A ceramic vase that cost an antique store $5 was marked $20. What is the percentage markup on the price of the ceramic vase?

Mathematics
1 answer:
Anika [276]3 years ago
8 0
The answer would be 75%%%%
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7. A scatter plot was created to show the relationship
Ksju [112]

Answer:

1020 students

Step-by-step explanation:

Given the trend line equation :

y = 0.1x + 18,

where y is the total number of staff members and x is the total number of students.

Using the equation, the predicted number of students in a school with 120 staffs ;

y = 120

y = 0.1x + 18

120 = 0.1x + 18

120 - 18 = 0.1x

102 = 0.1x

x = 102 / 0.1

= 1020 students

7 0
3 years ago
The sum of three consecutive integers is -75.
rusak2 [61]

Answer:

Suppose 3 consecutive integers are X-1,X,X+1

Step-by-step explanation:

Sum = X-1+X+X+1= -78

            3X=-78

             X= -78/3

             X= -26

3 consecutive integers are, -27, -26,-25.

smallest integer is -27

8 0
3 years ago
How much space is given for each parking spot at the mall parking lot if each spot has an equal width?
Akimi4 [234]
Assuming that the lengths are all the same, which they are usually regulated by federal law, the space will be the area (l x w)
7 0
3 years ago
What is the value of z so that -9 and 9 are both solution of x^2+z=103
Marysya12 [62]
22 because -9 and 9 squared is 81 subtract that from 103
4 0
3 years ago
Read 2 more answers
can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

7 0
3 years ago
Read 2 more answers
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