Answer:
We also drew a graph with 2 examples.
Step-by-step explanation:
If we have the line segment CD, we can divide it by 4: 1 as follows:
If point C has the coordinates (x1, z1) and point D has the coordinates (x2, z2), we calculate coordinate the points Y as follows:
y1 = (x2-x1) · 4/5
y2 = (z2-z1) · 4/5
In this way we have obtained the point Y with the coordinates (y1, y2), and the point Y divides the line segment CD by 4:1.
We also drew a graph with 2 examples.
Y=5/2 should be the answer
Answer:
2500 Square meters
Step-by-step explanation:
Given the garden area (as a function of its width) as:

The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.
A'(w)=-2w+100
-2w+100=0
-2w=-100
w=50 meters
Since Marquise has 200 meters of fencing to build a rectangular garden,
Perimeter of the proposed garden=200 meters
Perimeter=2(l+w)
2(l+50)=200
2l+100=200
2l=200-100=100
l=50 meters
The dimensions that will yield the maximum area are therefore:
Length =50 meters
Width=50 meters
Maximum Area Possible =50 X 50 =<u>2500 square meters.</u>
3(4m-2)-2(m+5)
Distribute.
12m-6-2m-10
12m-2m= 10m
-6-10= -16
10m-16
I hope this helps!
~kaikers