The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
angle of arc ACB = 360° - 35° = 325°
The length of major arc ACB = (325/360) * π * 10 = (325/36)π
The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π
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Answer:
x = 2
Step-by-step explanation:
You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operation, and =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction.
First, subtract 25 from both sides of the equation:
5x + 25 (-25) = 35 (-25)
5x = 35 - 25
5x = 10
Isolate the variable, x. Divide 5 from both sides:
(5x)/5 = (10)/5
x = 10/5
x = 2
x = 2 is your answer.
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Answer:
75
Step-by-step explanation:
For this, you need to solve a proportion-
3.4 x
----- = -----
1.8 39.75
3.4*39.75=135.15
135.15/1.8= 75.0833.....
75.0833.. is rounded to 75
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
The answer to the equation is x < 2.