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Bad White [126]
3 years ago
7

Can someone help me with this one real quick ? Thanks a lot! Please explain and show your work :)

Mathematics
1 answer:
marin [14]3 years ago
6 0
A. Given.
You were given the proof.

b. Corresponding angles are congruent.
Since angles 1 and 2 are corresponding, then if one is 130, then the other one is also 130.

c. Vertical angles are congruent.
Angles 2 and 3 are vertical, meaning they'll also be congruent.

d. Transitive Property of Equality.
If angles 2 and 3 are vertical, then if 2 is 130, then 3 is also 130.
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2. Lynn filled up her gas tank on the way home from work. She uses about 1.6
Gelneren [198K]

The amount of gas in her tank after 8 days given the linear equation g = 213 - 1.6d is 200.2 gallons of gas

<h3>Linear equation</h3><h3 />
  • Gallons of gas used per day = 1.6 gallons
  • Number of days = d
  • Quantity of gas = g

The equation

g = 213 - 1.6d

Gas remaining after 8 days

g = 213 - 1.6(8)

= 213 - 12.8

g = 200.2 gallons of gas

Learn more about equation:

brainly.com/question/1884491

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2 years ago
Please guys help me. I will give you the brainliest​. Answer what you know
Igoryamba

Answer:

number 3 is B and number 4 is C

Step-by-step explanation:

7n-1

the 5th term of the sequence 4n+1

5 0
3 years ago
Solve the system. 2x + y = 3 −2y = 14 − 6x Write each equation in slope-intercept form.
barxatty [35]

Answer:

2x + y = 3

y = -2x + 3 <==

-2y = 14 - 6x

y = -14/2 + 6/2x

y = -7 + 3x

y = 3x - 7 <===

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Identify all of the following solutions of square root of x plus 14 end root plus 2 equals x.
BabaBlast [244]
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5 0
3 years ago
Read 2 more answers
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
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