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kobusy [5.1K]
3 years ago
9

Part 6: please assist me with these problems​

Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0

Answer:  12) 34°     13) 90°

<u>Step-by-step explanation:</u>

\text{Law of Sines:}\quad \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

12) Given: a = 10.2,  b = 6.8, A = 122°

\dfrac{\sin 122^o}{10.2}=\dfrac{\sin B}{6.8}\\\\\\\dfrac{6.8\sin 122^o}{10.2}=\sin B\\\\\\\sin^{-1}\bigg(\dfrac{6.8\sin 122^o}{10.2}\bigg)=B\\\\\\34.4^o=B

*****************************************************************************

Law of Cosines: a² = b² + c² - 2bc · cos A

<em>Note: The letters can be swapped</em>

13) Given: a = 3,  b = 4,  c = 5, C = ???

3² = 4² + 5² - 2(4)(5) · cos C

9  = 16 + 25 - 40 cos C

9 = 41 - 40 cos C

-32 = -40 cos C

0.8 = cos C

90° = C

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