Part A: W = 6x
Part B: Since without overtime it is 6 $ per hour and you need to make 40 hours
you would multiply 6 *40 = 240
So <u>S = 240 + 9y
</u>Part C: <u><em>Substitute</em></u><u />
Since Andrew earned 330 you would substitute it for <em>S</em>
<u>
330 = 240 + 9y</u> <--- solve for <u /><u><em>y</em><em /></u><em />
330 ( - 240 ) = 240 ( - 240 ) 9y < ---- subtract 240 from each side
90 = 9y
90 / 9 = 9y / 9 <----- divide by 9
10 =y Andrew worked 10 hours for overtime
<u><em /></u><u><em /></u><em /><u><em>Check </em></u><u><em /></u><em />
<u><em />
</u><u><em>330</em></u><u><em /></u><em> </em>= 240 + 9(10)
<u><em>330</em></u><u><em /></u><em /> = 240 + 90
<u><em>330</em></u><u><em /></u><em /> = 330 <-- your answer is <u><em>10</em></u>
Answer: dewwkmldnfkbgrfkhuiejdowks;ldsbjhienesdljknew.mdasx;oj
Step-by-step explanation:
Answer: 0.6826894
Step-by-step explanation:
Given : The length of similar components produced by a company are approximated by a normal distribution model with a
5 cm and a
0.02 cm.
Let x be the random variable that represents the length of similar components produced by a company.
z-score : ![\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x= 4.98
![\dfrac{4.98-5}{0.02}=-1](https://tex.z-dn.net/?f=%5Cdfrac%7B4.98-5%7D%7B0.02%7D%3D-1)
For x= 5.02
![\dfrac{5.02-5}{0.02}=1](https://tex.z-dn.net/?f=%5Cdfrac%7B5.02-5%7D%7B0.02%7D%3D1)
By using the standard z-value table (right -tailed) , the probability that the length of this component is between 4.98 and 5.02 will be :_
![P(4.98](https://tex.z-dn.net/?f=P%284.98%3Cx%3C62000%29%3DP%28-1%3Cz%3C1%29%3D1-2P%28z%3E%7C1%7C%29%5C%20%5C%20%5C%5C%5C%5C%3D1-2P%28Z%3E%7Cz%7C%29%5D%5C%5C%5C%5C%3D1-2%280.1586553%29%5C%5C%5C%5C%3D0.6826894)
Hence, the probability that the length of this component is between 4.98 and 5.02= 0.6826894
The answer could be -120 in a simplified form
60% divided by 6 = 10%
660 divided by 6 =110
10% x 10 = 100%
110 x 10 = 1100