ANSWER
The correct answer is A
<u>EXPLANATION</u>
From the equation 
<u>L.H.S.</u>
Fe = 1
O =2
<u> R.H.S</u>
Fe =2
O =3
Now, let try to balance the oxygen atoms first,
To do this, we know the Least Common Multiples of 2 and 3 is 6
To get 6 atoms of oxygen at L.H.S multiply 2 by 3 and on the R.H.S, multiply 3 by 2
L.H.S.
R.H.S
This means that, 3 should be in front of 
at the L.H.S and 2 should come before 
in the R.H.S of the equation
Now, we have
L.H.S.
Fe = 1
O = 6
<u>R.H.S</u>
Fe =4
O =6
The equation is still not balanced since Fe is not balance
The Least Common Multiple of 1 and 4 is 4
Which means that we need to multiply 1 by 4 at the L.H.S and 4 by 1 at the R.H.S
L.H.S.
R.H.S
We now, have
<u>L.H.S. </u>
Fe= 4
O=6
<u>R.H.S</u>
Fe =4
O=6
Hence the balanced equation is
Answer:
The correct answer would be C.) The cell grows and makes a copy of its genetic material.
Cell cycle can be divided into two phases namely; inter-phase and mitotic phase.
Inter-phase or resting phase is the phase occurs between two consecutive mitotic phases.
It is sub-divided into three phases:
Gap 1 (G₁) phase: The cell actively performs its functions during this phase. It grows in size, transcribe and translate all the enzymes, proteins and other components which are necessary for replication of DNA (deoxyribonucleic acid).
Synthesis (S) phase: It is the phase during which DNA content of the cell is replicated or synthesized. After this phase, the DNA content of the cell doubles however, the chromosome number remains the same.
Gap 2 (G₂) phase: The cell resumes its growth and prepares itself for cell division or mitotic phase. The cell organelles like mitochondria and chloroplasts (in plants) also divide during this phase. The cell continues to grow until it enters mitotic phase.
Hence, we can conclude that the cell grows and makes copy of its genetic material ( usually DNA) before mitosis.
I am assuming that since you are in a biology class, you are looking for the answer: cells.
Hope this helps! <3
No more than five trophic levels are present in an ecosystem, most have only 4.
Answer:
We know that there are 200 guanine bases so there will be 200 cytosine bases also.
According to Chargaff’s base pair rule,
G+A=T+C=600,
A+200+T+200=600 (since total bases are 600)
A+T+400=600
A+T=200
since there is 50% adenine and 50% thymine , A=100, T=100, G=200, C=200
Verification
A+T+G+C=600
100+100+200+200=600
600=600
Explanation:
