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laiz [17]
4 years ago
6

Ginny has two vegetable gardens. In the first garden, Ginny grows tomatoes

Mathematics
1 answer:
zloy xaker [14]4 years ago
3 0
We are finding the least common multiple
the least common multiple of 2and3 is 6
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A town predicts that its population will double in e ^ In 10/ 2 In e years.
Sophie [7]

\dfrac{e^{\ln 10}}{2\ln e}=\dfrac{10}{2}=5

6 0
4 years ago
Read 2 more answers
Bela started studying how the number of branches on her tree grows over time. Every 2.9 years, the number of
kati45 [8]

Answer:

 The required function that models the number of branches t years since Bela began studying her tree is

number of branches = 60(1.83)^{\frac{t}{2.9} }

Step-by-step explanation:

Let t be the time in years

Initially Bela's tree had 60 branches.

therefore the function that can be used to model the number of branches after t years will be given by

number of branches( after t years) = 60\times(1 + \frac{83}{100})^{\frac{t}{2.9} } = 60(1.83)^{\frac{t}{2.9} }

7 0
3 years ago
Match the vocabulary to the correct operation PLZ ANSWER:(
MaRussiya [10]
Product=multiplication
Sum=addition
Difference=subtraction
Quotient=division
Quantity=parentheses
4 0
4 years ago
6x - 2y = -22<br> х+4y = -8
maksim [4K]

Answer:

x = -4    y = -1

Step-by-step explanation:

x + 4y = -8

4y = -x - 8

y = -1/4x - 2

6x - 2(-1/4x - 2) = -22

6x + 1/2x + 4 = -22

13/2x + 4 = -22

13/2x = -26

x = -4

(-4) + 4y = -8

-4 + 4y = -8

4y = -4

y = -1

6 0
3 years ago
Read 2 more answers
Write the equation of an ellipse with vertices at (7, 0) and (-7, 0) and co-vertices at (0, 1) and (0, -1).
Irina-Kira [14]

Answer:

\frac{(x)^{2}}{49}+\frac{(y)^{2}}{1}=1

Step-by-step explanation:

In this problem we have a horizontal ellipse, because the major axis is the x-axis

The equation of a horizontal ellipse is equal to

\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}} =1

where

(h,k) is the center of the ellipse

a and b  are the respective vertices distances from center

we have

vertices at (7, 0) and (-7, 0)

co-vertices at (0, 1) and (0, -1)

so

The center is the origin (0.0) (The center is the midpoint of the vertices)

a=7

b=1

substitute

\frac{(x-0)^{2}}{7^{2}}+\frac{(y-0)^{2}}{1^{2}}=1

\frac{(x)^{2}}{49}+\frac{(y)^{2}}{1}=1

8 0
3 years ago
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