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2 years ago

What is an equivalent expression to 5( x plus 3y)

Mathematics

1 answer:

WARRIOR [948]2 years ago

5 0

Step-by-step explanation:

The answer is 5x + 15y. I'm pretty sure.

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Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago

Find the L.C.M of 6,12,18

Rashid [163]

The least common multiple is 36.

6x6= 36
12x3=36
18x2=36

3 0

3 years ago

Which steps show how to use the distributive property to evaluate 7 . 82?

ryzh [129]

Answer is sus/11:,677(,//linkS.org

5 0

2 years ago

Are there any integers between 0 and 1? explain?

Ulleksa [173]

No. there are no integers between 0 and 1 because integers are the numbers which don't have any fractions and decimals. between 0 and 1 only decimals and fractions are present

7 0

3 years ago

Read 2 more answers

Why is the answer B? Plz explain.

sergeinik [125]

For line l to intersect line m at point (2, 1/2), line m must have the point (2,1/2) on its graph. It is implied that line l already has the point (2, 1/2). If line m does not have it, then there will be no intersection at that specific point.

Try checking every choice to see if it has point (2,1/2) on the graph.
Note that (x,y) = (2,1/2); check by using x=2 and y=1/2.

For A,

2x = y/2
2(2) = (1/2) / 2
4 ≠ 1/4

Cannot be choice A as it results in a false equation; this choice will not go through (2,1/2)

For B:

2y = 3 - x
2(1/2) = 3 - 2
1 = 1

This is a true equation so the point (2,1/2) is on the graph of 2y=3-x. This means that if this is the equation for line m, then line m will have a point at (2,1/2) and therefore intersect with line l. Therefore, B is the answer.

The rest of the choices are false as shown:

For C:

2x + 4y = 8
2(2) + 4(1/2) = 8
4 + 2 = 8
6 ≠ 8

Cannot be choice C as it results in a false equation; this choice will not go through (2,1/2)

For D:

y = 4 - (5/4)x
1/2 = 4 - (5/4)(2)
1/2 = 4 - 5/2
1/2 = 8/2 - 5/2
1/2≠ 3/2

Cannot be choice D as it results in a false equation; this choice will not go through (2,1/2)

4 0

3 years ago